Question

In an election between two candidates, A got 20% votes more than B and won by 2000 votes. In the subsequent election, 25% of the people who voted for A gave their votes to B. If everyone else voted as earlier, approx. what percentage of the total votes did A get in the second election?

Answer 1

Therefore A got =40.91% votes.

Step-by-step explanation:

Let B got  = x vote

Then A got =$\frac{100+20}{100} x$$=\frac{6}{5} x$

According to the problem,

$\frac{6}{5} x-x=2000$

$\Rightarrow \frac{1}{5} x =2000$

⇒x =10000

Therefore A got = $\frac{6}{5} \times 10000=12000$  votes

and B got 10000 vote.

In second election 25% of the people who voted for A gave their votes for B.

∴25% of 12000

= $\frac{25}{100} \times 12000$

=3000

∴In second election A got (12000-3000)=9000 votes

Total voter =  (12000+10000)=22000

Therefore A got$=(\frac{9000}{22000} \times 100)\%$  =40.91% votes

Answer 2

Answer: 45%

Step-by-step explanation: