Question

In an election candidate A had secured 12% vote more than candidate B. By how much percent had candidate B less than candidate A

Answer 1

Answer:

7%

Step-by-step explanation:

Let take seats of B be x

A= x+12x/100

A=112x/100= 56x/50= 28x/25

Peecenta B less than A

(28x/25 - x)/28x/25 ×100

3x/ 25 ×25/28x ×100

300/28%= 150/14%= 75/7%= 10 whole 5 by 7 %

Answer 2

Given: In an election candidate, A had secured 12% vote more than candidate B.

To find: We have to find by how much per cent had candidate B less than candidate A.

Solution:

To determine the by how much per cent had candidate B less than candidate A we have to follow the below steps-

Let B has secured 100 votes.

A had secured 12% vote more than candidate B.

Thus A has secured 100+12=112 votes.

Thus the percentage of votes B gets less than A is given as-

$\frac{112 - 100}{112} \times 100 \\ = 10.71$

Thus by 10.71% candidate B had secured fewer votes than candidate A.