In an election contested by two parties, party d secured 12% of the total votes more than party r. If party r got 132,000 votes, by how many votes did it lose the election shortcut
Answers
Answered by
36
Answer:
36000
Step-by-step explanation:
Let Assume total votes = 100V
Party D got = 12V + 132000
Party r Got = 132000
132000 + 12V + 132000 = 100V
88 V = 264000
V = 3000
Party R lost by 12V
12 V = 36000
amitnrw:
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Answered by
1
Answer:
let the total votes be X
X*12/100 + 132000 = X - 132000
ON SOLVING THIS EQUATION FURTHER WE GET
26400000 = 88X
X= 300000
THEREFORE, 300000 - 132000 =168000 ( THE WINNING PARTY"S VOTES
DIFFERENCE = 168000-132000 =N 36000 ( ANSWER)
Step-by-step explanation:
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