Math, asked by Aanchaldhingra7186, 1 year ago

In an election contested by two parties, party d secured 12% of the total votes more than party r. If party r got 132,000 votes, by how many votes did it lose the election shortcut

Answers

Answered by amitnrw
36

Answer:

36000

Step-by-step explanation:

Let Assume total votes = 100V

Party D got = 12V + 132000

Party r Got = 132000

132000 + 12V + 132000 = 100V

88 V = 264000

V = 3000

Party R lost by 12V

12 V = 36000


amitnrw: Please mark the answer as "The Brainliest answer" if it helps
Answered by shreyagupta7565
1

Answer:

let the total votes be X

X*12/100 + 132000 = X - 132000

ON SOLVING THIS EQUATION FURTHER WE GET

    26400000 = 88X

    X= 300000

THEREFORE, 300000 - 132000 =168000 ( THE WINNING PARTY"S VOTES

DIFFERENCE = 168000-132000 =N 36000 ( ANSWER)

Step-by-step explanation:

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