Question

In an election only two candidates a and b contested 30% of the voters did not vote and 1600 votes were declared as invalid. the winner, a got 4800 votes more than his opponent thus he secured 51% votes of the total voters on the voter list. percentage votes of the loser candidate, b out of the total voters on the voter list is:

Answer 1

%b=3 %a=51 %did not vote=30 %invalid =16 add up to 100%.

It will be greatly compelling. May there be x voters and k votes goes to washout then 0.8x - 120 = k + (k + 200) k+200 = 0.41

=> k = 1440 and (k + 200) =1640, consequently 1440/3200 x 100 = 45%

Answer 2

Answer:Total voters:100%

30%did not vote,so 70%votes cast

1600 votes are invalid

valid votes=70%-1600

Step-by-step explanation: winner got 51% of total voters list and 4800 more than loser.

so loser got 51%-4800

add winner and loser and equalize with valid votes

51%+51%-4800=70%-1600

1%=100

loser votes=300/10000(total votes)

=3%