Math, asked by 123123dev, 1 year ago

In an election, there were only two candidates. The winner got 53% votes and won by 9600 votes. Find the total number of votes polled.

Answers

Answered by rohitroy0503
65

so your answer is here                                                                                                                  

total 100% people

winner got 53% vote

losser on got remaining 47% vote

so total no of voters is 9600/6×100=160000


123123dev: Ye 6 kahan se aaya jis se 9600 ko divide kiya h
rohitroy0503: diffrence between winniner and losser candidate 53-47=6
Answered by wifilethbridge
85

Answer:

160000

Step-by-step explanation:

Let the total no. of poles be x

The winner got 53% votes

So, failure got votes = 100% - 53% = 47%

So, winner got votes = 0.53x

Loser got votes = 0.47x

We are given that The winner got 53% votes and won by 9600 votes

So, 0.53x-0.47x=9600\\0.06x = 9600\\x=\frac{9600}{0.06}\\x= 160000

Hence the total number of votes polled is 160000

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