Question

In an election, there were two candidates A and B. The total number of voters in this constituency was 80,000 and 90% of the total votes were polled. If 60% of the polled votes were cast in favour of A, how many votes were received by B? Explain it

Answer 1

Answer:

28,800

Step-by-step explanation:

Multiply 80,000 voters by 0.9(90%) to get the polled votes

80,000 x 0.9=72,000(polled votes)

then,multiply the polled votes by 0.6(60%) that are in favor of candidate A

72,000 x 0.6 =43,200(in favor of candidate A)

Finally,subtract those in favor of A to the polled votes to know how many votes were received by B

72,000-43,200=28,000(votes received by B)