Question

In an election,there were two candidates A and B.The total number of voters in this constituency was 60000 and 80% of the total votes were polled.If 60% of the polled votes were cast in favour of A,how many votes were received by B?

Answer 1

Total number of votes=60000

Percentage of total votes polled=80% of 60000=80/100*60000=48000

Votes polled for A=60% of 48000=60/100*48000=28800

Votes received by B=48000-28800=19200 ans...

Answer 2

Answer:

19200

Step-by-step explanation:

Votes polled = 80% of 60000

i.e 80/100*60000

=48000

 

Votes received by B is 100%- 60%  

=40%

therefore votes received by B is 40/100 * 48000

=19200