Question

in an election there were two candidates A and B the total number of voters in this constituency was 60000 and 80% of the total votes were called if 60% of the cold votes were cast in favour of a how many votes were received by b​

Answer 1

total voters =6000 votes polled=80%
=80/100*6000.
=4800
votes polled by a= 60%
votes polled by b =100%-60%
=40%
40/100*4800 =1920votes are polled by b

Answer 2

Hii Mates,...

Votes polled = 80% of 60000

i.e 80/100 × 60000

=48000

Votes received by B is 100%- 60%

=40%

Therefore votes received by B is

40/100 × 48000

=19200

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