In an election, there were two candidates A and B. The total number of voters in this constituency was 60000 and 80% of the total votes were polled. If 60% of the polled votes were cast in favour of A, how many votes were received by B? Explain it
Answers
i.e 80/100*60000
=48000
Votes received by B is 100%- 60%
=40%
therefore votes received by B is 40/100 * 48000
=19200
Given,
In an election, there were two candidates A and B.
The total number of voters in this constituency = 60000
The percentage of the total votes polled = 80%
Percentage of polled votes cast in favor of A = 60%
To find,
The number of votes received by B.
Solution,
We can simply solve this mathematical problem using the following process:
According to the question;
The total number of votes polled = 80% of the total number of voters in this constituency
= 80% of 60,000
= 80/100 × 60,000
= (4×60,000)/5
= 48,000
Now, according to the question;
Percentage of polled votes cast in favor of B
= 100% - (percentage of polled votes cast in favor of A)
= 100% - 60%
= 40%
So, the total number of votes cast in favor of B
= 40% of the total number of votes polled
= 40% of 48,000
= 40/100 × 48,000
= (2×48,000)/5
= 19,200
Hence, 19,200 votes are received by B.