Question

in an election three candidates contested the first candidate got 40% votes while the s3cond got 36% votes how many votes did the third candidate get if total 36000 votes were polled​

Answer 1

Answer:

8640

Step-by-step explanation:

40 percent plus 36 percent

ans=76 percent

100 percent minus 76 percent

ans = 24 percent

24 percent of 36000

ans=8640

Answer 2

Given:-

Total votes polled = 36000

Number of votes gained by first candidate =

40% of 36000 = 40×36000/100= 14400

Number of votes gained by second candidate =

36% of 36000 = 36×36000/100 = 12960

Now we get to know that the votes gained by all candidates will be equal to the total number of votes polled. So to find out the number of votes gained by the third candidate is equal to the total polls done reduced by the votes gained by first candidate and the second candidate.

The first candidate got 14400 votes and the second candidate got 12960 votes. Hence,

Votes gained by third candidate = 36000- 14400-12960 = 8640

So the third candidate got 8640 votes.

This was the basic approach if you want to solve it in much lesser time then let's follow a different and fast approach.

Approach 2:-

Since the First and second candidates got 40% and 36% of the polls , so obviously the third candidate has got the remaining percentage of votes.

Remaining percentage= 100-40-36= 24

Votes gained by third candidate = 24% of 36000 = 24×36000/100 =8640 votes.