Plz answer this question fast !!
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In right triangle OAB
AB/OA =tan30
r1/10=1/√3
r1=10/√3cm
In right triangle OCD
CD/OC=tan30
r2/20=1/√3
r2=20/√3cm
Volume of frustum of a cone=volume of cylinder wire
1/3×π×h(r²1+r²2+r1×r2)=πr²h(h of the wire)
1/3×10((10/√3)²+(20/√3)²+(10/√3)(20/√3))=1/32×1/32×h
10/3(100+400+200/3)×32×32=h
h=7000/9×32×32
h=7000×1024/9
h=7168000/9
h=7964.44m
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