Question

In an electric circuit resistance of 1,2,3 ohm are joint in a parallel combination if we connect the combination with 6 volt battery then determine the current in circuit ?

Answer 1

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TO FIND:

The Current In The Circuit Is:

GIVEN:

Three resistance in parallel 1,2&3 ohm

battery[V]=6volt

The effective resistance in circuit[R]

=1*2*3/1+2+3

=6/6

R=1

V=I*R

6=I*1

I=6

Thus the current in circuit is 6 Amp

Answer 2

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"Ohm's law states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance, and inversely proportional to the resistance of the circuit."

Given:

Resistance of 1 ,2 , 3 Ohm Are joint in parallel combination.

These combinations are connected with the battery of Potential Difference(V) = 6 volt

To Find :-

Current in the circuit (I)=?

Soln;

From the Ohm's Law ,

V = I R

I = R/V. .......1)

T find the Total resistance ,

As the resistances are connected in parallel combinations,

Let the Resistances be R1 , R2 and DE respectively

So, the total resistance (R)

=>

1/R = 1/R1 + 1/R2 +1/R3

1/R = 1+1/2+1/3

1/R = 11/6

R = 6/11

NOW,

I = R/V

I = 11/36 AMPHERE