Question

In an electric circuit two resistors of 2 ohm and 4ohm respectively are connected in series to a 6v battery.The heat dissipated by the 4 ohm resistor in 5s will be?

Answer 1

two resistors 2ohm and 4 ohm are connected in series . so the total resistance is 6 ohm

given v=6v

i = v/r

i = 6/6

i=1 A

new r= 4ohm

t=5s

h = i square rt

h= 1^2 (4)(5)

h = 20 joule

Answer 2

The heat dissipated by the 4 ohm resistor in 5 s will be 20 joules.

Explanation:

It is given that,

Resistance, $R_1=2\ \Omega$

Resistance, $R_2=4\ \Omega$

It is mentioned that both resistances are in series whose equivalent is given by :

$R=R_1+R_2$

$R=2+4$

R = 6 ohms

In series combination current throughout the circuit is same. It is given by :

V= IR

$I=\dfrac{V}{R}$

$I=\dfrac{6}{6}$

I = 1 A

We need to find the heat dissipated by the 4 ohm resistor in 5 s. It i given by :

$H=I^2Rt$

$H=(1)^2\times 4\times 5$

H = 20 Joules

So, the heat dissipated by the 4 ohm resistor in 5 s will be 20 joules. Hence, this is the required solution.

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