Question

In an electric heater, on flowing 3 amp current for 4 min 1080 kj heat is produced . the resistance of wire of heater is:

Answer 1

Explanation:

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Answer 2

Answer:

current=3A

time=4×60sec=2400sec

heat=1080Kj

we know,

H=I²Rt

by putting the values in the formula we get,

1080=3²×R×2400

R=1080/2400×3²

R=4.05ohm

Explanation:

hope it helps

Afi