Question

In an electrolysis of mcl3 0.15g of metal was deposited on the cathode by the passing of 1a current foe 6 min the atomic mass of m is

Answer 1

Answer:

Explanation:

W= (itE)/96500=1*6*60*E/96500

=> .15 = E/268.06

=> E = .15*268.06

       = .......