Question

In an equation
1)a+b=8
2)a+c=13
3)b+d=8 and
4)c-d=6
what is the value of a, b, c and d? ​

Answer 1

Answer:

a+b=8 a=8-b

a+c=13 a=13-c

so 8-b=13-c b=c-5

b+d=8 b=8-d

c-5=8-d c=13-d

c-d=6 c=6+d

13-d=6+d 2d=7 d=7/2

c=6+7/2=19/2

b=8-7/2=9/2

a=13-19/2=7/2

so ........a=7/2 b=9/2 c=19/2 d=7/2.......

verify

a+b=8

7/2+9/2=8

16/2=8 8=8 Rhs=Lhs

a+c=13

7/2+19/2=26/2=13 proved

b+d=8 9/2+7/2=16/2=8

proved

c-d=6 19/2-7/2=12/2=6

hence proved