in an equation x^2+mx+n=0 where m and n are integers..... if the only possible value for x= -3... find m
Anonymous:
it is not possible to find the exact value of m, but m can be found in terms of n
okk thanks
Answers
Answered by
1
x^2 + mx + n = 0
9 - 3m + n = 0
n - 3m = -9
3m = n + 9
m = (n+9)/3
9 - 3m + n = 0
n - 3m = -9
3m = n + 9
m = (n+9)/3
hope you found it helpful pls mark brainliest
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Answered by
1
since there is only one solution of x therefore m^2-8n=0
m^2=8n
now as x= -3
(-3)^2-3m+n=0
9-3m+n=0
9-3m+m^2/8=0
m^2-24m+72=0
now by solving this equation u can find m
m^2=8n
now as x= -3
(-3)^2-3m+n=0
9-3m+n=0
9-3m+m^2/8=0
m^2-24m+72=0
now by solving this equation u can find m
why 8m
how did you get m^2 - 8n = 0
srry its 8n
yess how
discriminant is zero..
ohkk...
thanks
my pleasure:)
;-)
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