In an equilateral triangle ABC, if AD is parallel to BC. Prove that 3AB^2 = 4AD^2.
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Answered by
1
Step-by-step explanation:
Is the answer
Hope it is helpful
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Answered by
1
Step-by-step explanation:
Given:
AABC is an equilateral triangle.
AD perpendicular to BC.
To Prove:
3AB? = 4AD2
Proof:
In AADB and AADC,
<ADB = <ADC = 90° (R)
AB = AC ( hypotenuse)(H)
AD = AD ( common side )(S)
Therefore,
In AADB,
AB2 = AD2 + BD2
PLEASE REFER THE IMAGE GIVEN HERE
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