In an equilateral triangle AD┴BC, what is the length of AD,
if the side of the triangle is a unit?
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Answer:
If one side of triangle= 1 unit
Area= √s(s-a)(s-b)(s-c)
also (1/2)b*h
√1.5(0.5)(0.5)(0.5)=(1/2)*1*(AD)
0.43=(1/2)*1*(AD)
2(0.43)=AD
Therefore, AD= 0.86
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