Question

In an equilateral triangle of side 24 cm find the length of the altitude

Answer 1

hope this help u.....

Answer 2

Answer:

Step-by-step explanation:

It is given that side of an equilateral triangle is 24cm, then

Area of equilateral triangle ABC is=$\frac{\sqrt{3}}{4}s^{2}=\frac{\sqrt{3}}{4}{\times}24{\times}24$               (where s is the side of equilateral triangle).

=$144\sqrt{3}cm^{2}$

now, Area of triangle ADC=$\frac{1}{2}{\times}base{\times}height$

$144\sqrt{3}cm^{2}$=$\frac{1}{2}{\times}24{\times}h$

$12h=144\sqrt{3}$

$h=12\sqrt{3}cm$

Thus, the length of the altitude is $12\sqrt{3}cm$