Question

in an exam a scored 60% more than the pass marks and he scored 30 marks less than the maximum marks if I scored 80% of the maximum what is the pass marks

Answer 1

Answer:

Let ;

The passing marks = x

The maximum Marks = y

The obtained marks = z.

Now, according to the question,

Obtained marks is 60% more than passing marks.

=> z = x + 60% of x

=> z = x + (60/100)x

=> z = x + 3x/5

=> z = (5x + 3x)/5

=> z = 8x/5 ---------(1)

Also;

Obtained marks is 30 less than the maximum marks.

=> z = y - 30 ---------(2)

Also,

Obtained marks is 80% of maximum marks.

=> z = 80% of y

=> z = (80/100)y

=> z = 4y/5 ------------(3)

From eq-(2) and (3) ,

we have;

=> y - 30 = 4y/5

=> y - 4y/5 = 30

=> (5y - 4y)/5 = 30

=> y/5 = 30

=> y = 30•5

=> y = 150

Now, putting y = 150 in eq-(2) ,we get;

=> z = y - 30

=> z = 150 - 30

=> z = 120

Now, putting z = 120 in eq-(1) , we get;

=> z = 8x/5

=> 120 = 8x/5

=> x = 120•(5/8)

=> x = 45

Thus, the obtained marks is 45.

Answer 2

Answer:75

Step-by-step explanation:let max marks be 100

Given A scored 80% or 30marks less than the maximum marks.

I.e 20%-------30

So, 100%----- 150

80%-----120

He scored 60 more Passing marks(PM) or

160%of PM =120

PM =(120*5)/8= 75% (160%=8/5)