Question

In an examination 34% of the students failed in Mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then the percentage of students who passed in both the subjects was
(a) 56%
(b) 54%
(c) 50%
(d) 44%

Answer 1

Students failed in only maths = 34 - 20 = 14%

Students failed in only english = 42 - 20 = 22%

Total students failed = 14 + 22 + 20 = 56%

Total passed = 100 - 56 = 44%

(d) is the correct option

Answer 2

Answer: Option 'd' is correct.

Step-by-step explanation:

Since we have given that

Percentage of students failed in Mathematics = 34%

Percentage of students failed in Science = 42%

Percentage of students failed in both the students = 20%

According to questions,

$n(M\cup E)=n(M)+n(E)-n(M\cap E)\\\\n(M\cup E)=34+42-20\\\\n(M\cup E)=56\%$

Percentage of students who passed in both the subjects is given by

$100\%-56\5\\\\=44\%$

Hence, Option 'd' is correct.