In an examination 35% of total students failed in hindi,45%failed in english and 20%in both .find the percentage of those who passed in both subject
Answers
Answered by
51
A:failed in hindi
B:failed in english
n(A) =35
n(B)=45
n(AandB)=20
So n(AorB) =n(A) +n(B) - n(AandB)
=35+45-20
=60
Those who passed in both subjects =100-n(AorB)
=40% reqd ans
B:failed in english
n(A) =35
n(B)=45
n(AandB)=20
So n(AorB) =n(A) +n(B) - n(AandB)
=35+45-20
=60
Those who passed in both subjects =100-n(AorB)
=40% reqd ans
Answered by
8
Answer :
The number of student who pass in both Subjects are 40%.
Step by step explanation :
Hey Mate,
X is the number of students who fail in Hindi Subject
Y is the number of students who fail in English Subject.
Given Data :
n ( X ) = 35
n ( Y ) = 45
n ( X ∩ Y )=20
Now,
n( X ∪ B ) = n ( X ) + n ( Y ) - n( X ∩ Y )
n( X ∪ B ) = ( 35 + 45 ) - 20
n( X ∪ B ) = 80 - 20
n( X ∪ B ) = 60
So, The number of student who pass in both Subjects are :
=> 100 - n( X ∪ B )
=> 100 - 60
=> 40%
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