In an office, there are 108 tables and 132 chairs. if 1/6 of the tables and 1/4 of the chairs are broken. how many people can work in the office if each person requires one table and one chair?
Answers
Answer:
90 members
Step-by-step explanation:
Number of total tables = 108
Number of total chairs = 132
Number of broken tables = (1/6) of 108
= (1/6) x 108
= 18 tables
Number of broken chairs = (1/4) of 132
= (1/4) x 132
= 33 chairs
Number of remaining tables = (Number of total tables) — (Number of broken tables)
= 108 — 18
= 90 tables
Number of remaining chairs = (Number of total chairs) — (Number of broken chairs)
= 132 — 33
= 99 chairs
Given constraint;
A person needs a table and a chair to work.
So, the total number of people who could work in the office = 90 members (9 chairs will be kept aside as there are no tables)