In an examination, 80% of the students passed in English,85% in mathematics and 75% in both English and mathematics.If 40% students failed in the both subject, find the total no of students?
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No of students passed in English = 80%
No of students passed in Mathematics = 85%
Remaining the children both passed in Mathematics and English = 75%
So let there are X no of students
80% of X passed in Maths = (85/100)X = 17X/20
75 of X passed in both = (75/100)X = 3X/4
4X/5 - 3x/4 = x/ 29
17x/29 - 3x4 = x10
There for total students passed = 3x/4+ x/20 + x/ 19 = 18x/ 20 = 9×/10
And x/10 given in question
so x = 40 × 10 = 400
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