Math, asked by rajakumar453, 6 months ago

In an examination, 83% of the total examinees passed. If the number of
failures is 1190, find the total number of examinees.

Answers

Answered by Anonymous
5

Let the total no. of examinees be x

83% of total examinees has passed

Students failed = 100% - 83% = 17%

No. of failures is 1190

∴17\% \: of \: x = 1190 \\  \\ ∴ \frac{17}{100}  \times x = 1190 \\  \\ ∴x = \frac{1190 \times 100}{17}  \\  \\ ∴x = 7000

Thus, the total no. of examinees are 7000.

Similar questions