In an examination a candidate must get 30% marks to pass. A candidate who gets 220 marks fails by 11 marks. What is the maximum mark ?
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hey
here's your answer
given, total percent marks needed to pass=30%
and,total marks a student get and failed by 11 marks=220
thus, pass marks =220+11=231 marks
30%== 231
let 'x' be maximum marks
then, 30% of x = 231
=>30/100 × x= 231
=>3/10 × x = 231
=>3x/10 = 231
=>3x = 231×10
=>x = 2310/3 = 770
hence, maximum marks is 770 marks
here's your answer
given, total percent marks needed to pass=30%
and,total marks a student get and failed by 11 marks=220
thus, pass marks =220+11=231 marks
30%== 231
let 'x' be maximum marks
then, 30% of x = 231
=>30/100 × x= 231
=>3/10 × x = 231
=>3x/10 = 231
=>3x = 231×10
=>x = 2310/3 = 770
hence, maximum marks is 770 marks
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