Question

In an examination a got 10% marks less than b, who got 25% marks more than c, who got 20% marks less then

d. if a got 360 marks out of 500, the percentage of marks obtained by d was?

Answer 1

A got 360/500 * 100 = 72% 
(as per question)it is 90% of B. 
So B = 72 * 100 / 90 = 80%. 

Which was 125% of C. 
So C = 80 * 100 / 125 = 64%. 

Which was 80% of D. 
So D = 64 * 100 / 80 = 80%. 
=> D got 80% marks.

Answer 2

Answer:

80%

Step-by-step explanation:

Given : a got 10% marks less than b, who got 25% marks more than c, who got 20% marks less then  d.

To Find: if a got 360 marks out of 500, the percentage of marks obtained by d was?

Solution:

A got 360 marks out of 500

A' percentage = $\frac{360}{500} \times 100$

                      = $72\%$

We are given that  a got 10% marks less than b

So,it is 90% of B.  

So B = $\frac{72 \times 100}{90} = 80\%$

Which was 125% of C.  

So C = $\frac{80 \times 100}{125} = 64\%.$

Which was 80% of D.  

So$D = \frac{64 \times 100}{80} = 80\%.$

So, D got 80% marks.

Hence the percentage of marks obtained by d was 80%