In an examination a student has to answer 5 questions out of 9 questions,in which 2are compulsory.In how many ways a student can answer the questions?
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Answer:
No. of questions given = 9
No. of questions to be answered = 5
But 2 questions are compulsory
So the student has to answer the remaining 3 questions (5 – 2 = 3) from the remaining 7(9 – 2 = 7) questions which can be done in 7C3 ways
7C3 = (7 x 6 x 5)/(3 x 2 x 1) = 35.
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