Math, asked by singhankita184pedl0b, 1 year ago

in an examination a student requires 40 percent of the total marks to pass if rupa gets 185 marks and fails by 15 marks find the total marks

Answers

Answered by Anonymous
2
if he gets 15marks more then he will be pass
so passing marks=185+15=200
and passing %=40%
both r passing marks
SOOOO
200/40*100=500
total marks=500
hope you understand

Aryan0688: sorry yr i am solving linear equations in one variable where is the value of x bhai
Answered by AnIntrovert
47

\mathfrak{\large{\underline{\underline{Answer :}}}}

The total marks are 500.

\mathfrak{\large{\underline{\underline{Step-by-step\: explanation}}}}

\textsf{\underline{\underline{Given : }}}

Students needs = 40% to pass

Rula gets = 185 marks

Fails by = 15 marks

\textsf{\underline{\underline{To find :}}}

The total marks

\textsf{\underline{\underline{Solution : }}}

\textsf{Let the Total Marks be as x }

As Rula failed by 15, the marks she scored when added by 15 makes the passing marks.

\green{\boxed{\green{\boxed{\red{\sf{40\% \: of \: x = 185 + 15}}}}}}

\begin{lgathered}\begin{lgathered}\sf{\longrightarrow} \: 40\% \: of \: x = 185 + 15 \\ \\ \sf{\longrightarrow} \: \frac{40}{100} \times x = 185 + 15 \\ \\ \sf{\longrightarrow} \: \frac{40x}{100} = 200 \\ \\ \sf{\longrightarrow} \:40x = 200 \times 100 \\ \\ \sf{\longrightarrow} \:40x = 20000 \\ \\ \sf{\longrightarrow} \:x = \frac{20000}{40} \\ \\ \sf{\longrightarrow} \:x = 500\end{lgathered}\end{lgathered}

\textsf{Total Marks = 500 }

\therefore\textsf{The total marks are 500. }

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