Question

In an examination it is required to get 350 of the aggregate marks to pass . A student gets 32% marks and is declared failed by 70 marks . What are the maximum aggregate marks a student can get.?​

Answer 1

marks to pass =350

failed by =70

marks scored =280

(32/100)×T =280

T=28000/32=7000/8

=875

Answer 2

$\mathfrak{\huge{Answer:}}$

$\mathbb{GIVEN}$

Marks needed to pass the examination = 350 marks

The student gets 32 %

The student fails by 70 marks

$\mathbb{TO\:FIND}$

The total marks. Or say, the maximum marks a student can secure.

$\mathbb{METHOD}$

$\sf{Let\:the\:total\:marks\:be = x}$

Now, we're given that the marks needed to pass the examination are 350 marks. That means, if the student who got 32% fails by 70 marks, then the total passing marks will be = 32% of x + 70 marks

Algebraically, this statement means the same as :

$\tt{32}$ % $\tt{of\: x + 70 = 350}$

As this equation formed is in only $\bf{one}$ variable, the total marks can be found by further calculations.

=》 $\tt{\frac{32x}{100} = 350 - 70}$

=》 $\tt{x = \frac{28000}{32}}$

=》 $\tt{x = 875}$

Thus, the total marks are $\sf{\huge{875\:marks}}$