Question

In an examination,ramya got 9 marks less than twice that of udaya got.product of their marks is 195.Who got more marks?How much?​

Answer 1

Answer:

udaya get more marks than ramya which is 15.76.

Step-by-step explanation:

suppose marks of ramya = x and marks of udaya is y

so according to the question,

1) x=2y-9

and

2) x.y=195

now by the linear arithmetic formula

substitute the value of x from (1) eqution

(2y-9)y=195

2y^{2}-9y-195=0

after solving the equation by following formula

x=−b±√(b^2-4ac)/2a

we found

The discriminant b^2−4ac>0

so, there are two real roots.

which becomes

x=12.3773

x=−7.87731

consider the positive value x=12.37

y=195/x

y=195/12.37

y=15.76

Answer 2

Answer:

Ramya Got 3.38 more marks

Step-by-step explanation:

In an examination,ramya got 9 marks less than twice that of udaya got.product of their marks is 195.Who got more marks?How much?​

Let say Ramya Mark = R

Udaya Mark = U

ramya got 9 marks less than twice that of udaya got

R = 2U - 9

product of their marks is 195

RU = 195

(2U-9)U = 195

=> 2U² - 9U   = 195

=> 2U² - 9U - 195 = 0

=> U = (9 ± √(9² - (4×2×(-195))) )/(2 × 2)

=> U = (9 ± √(81 + 1560) )/4

=> U = (9 ± √(1641) )/4

=> U = (9 ± 40.51)/4

U = 49.51/4    as U can not be negative

U = 12.38

R = 2U - 9  =>  R = 2 × 12.38 - 9 = 15.76

Udaya Marks = 12.38

Ramya Marks = 15.76

Ramya Got 3.38 more marks  (15.76 - 12.38 = 3.38)