In an examination,ramya got 9 marks less than twice that of udaya got.product of their marks is 195.Who got more marks?How much?
Answers
Answer:
udaya get more marks than ramya which is 15.76.
Step-by-step explanation:
suppose marks of ramya = x and marks of udaya is y
so according to the question,
1) x=2y-9
and
2) x.y=195
now by the linear arithmetic formula
substitute the value of x from (1) eqution
(2y-9)y=195
2y^{2}-9y-195=0
after solving the equation by following formula
x=−b±√(b^2-4ac)/2a
we found
The discriminant b^2−4ac>0
so, there are two real roots.
which becomes
x=12.3773
x=−7.87731
consider the positive value x=12.37
y=195/x
y=195/12.37
y=15.76
Answer:
Ramya Got 3.38 more marks
Step-by-step explanation:
In an examination,ramya got 9 marks less than twice that of udaya got.product of their marks is 195.Who got more marks?How much?
Let say Ramya Mark = R
Udaya Mark = U
ramya got 9 marks less than twice that of udaya got
R = 2U - 9
product of their marks is 195
RU = 195
(2U-9)U = 195
=> 2U² - 9U = 195
=> 2U² - 9U - 195 = 0
=> U = (9 ± √(9² - (4×2×(-195))) )/(2 × 2)
=> U = (9 ± √(81 + 1560) )/4
=> U = (9 ± √(1641) )/4
=> U = (9 ± 40.51)/4
U = 49.51/4 as U can not be negative
U = 12.38
R = 2U - 9 => R = 2 × 12.38 - 9 = 15.76
Udaya Marks = 12.38
Ramya Marks = 15.76
Ramya Got 3.38 more marks (15.76 - 12.38 = 3.38)