Math, asked by ababb786, 8 months ago

In an examination, Ritika has to select 4 questions from each part. There are 6, 7 and 8 questions in Part I, Part II and Part III, respectively. What is the number of possible combinations in which she can choose the questions?​

Answers

Answered by brainlyboy1248
1

Required possible combinations

= 6C4×7C4×8C4

=

6×5

2×1

×

7×6×5

3×2×1

×

8×7×6×5

4×3×2×1

= 15×35×70 = 36750

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