Question

In an examination student has to get 35% to pass he got 30% and failed by 20 marks find maximum number

Answer 1

Heya !!

Here is your answer : -

Given,

Passing percentage of a exam = 35% ©

A student gets 30% marks and fails by 20 ® marks.

To find,

Maximum marks i.e total marks of examination

Main solution :

Let total marks be x.

Framing linear equation for case © :

Passing marks = 35% of x = $\frac{7x}{20}$ (€)

Framing linear equation for case ® :

Passing marks = 30% of x + 20 =
$\frac{3x}{10}$ + 20. (¥)

Now , equating equations € and ¥, as both of them represent total marks :

=>
$\frac{7x}{20}$ = $\frac{3x}{10}$ + 20.

=> Now, solving for x.

=> $\frac{7x}{20}$- $\frac{3x}{10}$ = 20

=> $\frac{x}{20}$ = 20

=> x = 400 marks

=> Total marks = x = 400 marks.

Hope it helps you.