In an examination, the number of participants from 5th standard is 265, number of participants from 6th standard is 159 and number of participants from 7th standard is 106. Find the minimum number of rooms required if in each room the same number of participants are to be seated and all of them being in the same standard.
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The no. of students seated in each room would be H.C.F of all the three values above.
60 =2×2×3×5
84=2×2×3×7
108=2×2×3×3×3
Therefore hcf = 12
Now no. of rooms required are total number of students divided by no. of students in each room.
* No of rooms= 60+84+108/12
=21
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