Math, asked by achahar07, 10 months ago


In an examination, the ratio of pass candidates to failed was 3: 1. If 8 more had appeared and
less had passed, then the ratio would have changed to 1:1. The number of candidates who
appeared for the examination is​

Answers

Answered by vmsravani
13

Answer:

Step-by-step explanation:

Given ratio of pass to fail candidates is 3:1

Let the number of passed candidates = 3x

Number of failed candidates = x

Hence the total number of candidates appeared for the exam = 3x + x = 4x

It is also given that if 8 more had appeared then the total number of candidates becomes (4x + 8)

It is also given that 6 candidates have passed less.

Hence number of candidates who passed = 3x – 6  

Therefore, the number of candidates who failed = Total candidates appeared – Number of candidates who have passed the exam

= (4x + 8) – (3x – 6)

= 4x + 8 – 3x + 6

= x + 14

Given that the ratio of passed to failed candidates becomes 1:1

 

3x – 6 = x + 14

2x = 20

∴ x = 10

Thus total number of candidates who appeared for the examination are 4x = 40.

Answered by shibnariyas0
3

Answer:

4x=40

Step-by-step explanation:

Hope it helps you....

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