In an examination, there are 3 papers of mathematics of 100 marks each. a boy secures 60% in the first paper and 70% in the second paper. in order to secure 70% in the aggregate, what percentage of marks he should secure in third paper?
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6marks obtained in first paper=60
marks obtained in second paper=70
let the obtained in third paper be x
then, A/QI
(130+x)/300×100=70
(130+x)/3=70
x=210-130
x=80
marks obtained in third paper=80
marks obtained in second paper=70
let the obtained in third paper be x
then, A/QI
(130+x)/300×100=70
(130+x)/3=70
x=210-130
x=80
marks obtained in third paper=80
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