Question

In an experiment , 1.288 g of copper oxide was obtained from 1.03 g of copper. In another experiment, 3.672 g of copper oxide gave, on reduction, 2.938 g of copper. Show that these figures verify the law of constant proportions. ​

Answer 1

Answer:

2Cu+O2→2CuO

1.03g 0.258g    1.288g

Therefore, since Mass of reactant=Mass of product

It is in accordance with law of conservation of Mass.

So, Ratio of OxygenRatio of Copper=0.2581.03=13.99=4:1

Explanation:

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Answer 2

Answer:

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