Math, asked by AnkitRao, 1 year ago

In an experiment, a coin is tossed 600 times. If the tail turns up 380 times, find the experimental probability of getting:
A. a head
B. a tail

Answers

Answered by saicharan06467
22
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Answered by VineetaGara
0

Given,

In an experiment, the number of times a coin is tossed = 600

Number of times tail turns up = 380 times

To find,

The experimental probability of getting:

A. a head

B. a tail

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

The probability of occurrence of a favorable event = P (favorable event)

= (Total number of occurrence of the favorable event) / (Total number of occurrence of all possible events)

= (Total number of occurrence of the favorable event) / (Total number of trials)

Now, according to the question;

Number of times head turns up

= (number of times a coin is tossed) - (number of times tail turns up)

= 600-380

= 220

A)

As per the question;

The favorable event is the occurrence of a head.

And, the total number of trials = 600

So, the probability of occurrence of a head

= P(occurrence of a head)

= (frequency of occurrence of a head)/(total number of trials)

= 220/600 = 11/30

B)

As per the question;

The favorable event is the occurrence of a tail.

And, the total number of trials = 600

So, the probability of occurrence of a tail

= P(occurrence of a tail)

= (frequency of occurrence of a tail)/(total number of trials)

= 380/600 = 19/30

Hence, the experimental probability of occurrence of a head is 11/30 and the experimental probability of occurrence of a tail is 19/30, respectively.

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