Question is attached pls answer
Attachments:
Answers
Answered by
1
conjugate
((2+√3)(2√3+3√2))/((3√2-2√3)(3√2+2√3))
(a+b)(a-b) =a^2-b^2
so 18-12=6
(4√3+6√2+6+3√6)/6
a=(2√3+3√2+3)/3
b=1/2
((2+√3)(2√3+3√2))/((3√2-2√3)(3√2+2√3))
(a+b)(a-b) =a^2-b^2
so 18-12=6
(4√3+6√2+6+3√6)/6
a=(2√3+3√2+3)/3
b=1/2
Similar questions