Question

In an experiment, a coin is tossed 600 times. If the tail turns up 380 times, find the experimental probability of getting (a) A head (b) A tail

Answer 1

hello !
It is sure that tail comes 380 times , out of 600 chances ,
then unknown results = 600 - 380 = 220 = Sample space
(a)
The chances of getting a head (H)= 1/2 × Sample space = 1/2×220 = 110
The probability of getting a head = Total chances oh head(H)/Sample space = 110 / 220 = 1/2
 (b)
The probability of getting a tail = 1 - 1/2 = 1/2
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Answer 2

Given,

Number of times a coin is tossed = 600

Number of times tail turns up = 380

Number of times head turns up = 220

To find,

a) the probability of getting a head

b) the probability of getting a tail.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

The probability of occurrence of a favorable event = P (favorable event)

= (Total number of occurrence of the favorable event) / (Total number of occurrence of all possible events)

= (Total number of occurrence of the favorable event) / (Total number of trials)

As per the given question;

The total number of trials = 250

Now,

The probability of getting a head

= P(getting a head)

= (frequency of occurrence of a head) / (total number of trials)

= 220/600

= 11/30

=> P(getting a head) = 11/30

And,

The probability of getting a tail

= P(getting a tail)

= (frequency of occurrence of a tail) / (total number of trials)

= 380/600

= 19/30

=> P(getting a tail) = 19/30

Hence, the probability of getting a head is 11/30 and the probability of getting a tail is 19/30, respectively.