Physics, asked by fatimakhan1254, 1 year ago

In an experiment of determining young's modulus of the material of a wire,the length as well as radius of the wire is doubled .the young's modulus will

Answers

Answered by abhi178
8
Young's modulus is the ratio of stress to strain.
where, stress is the force per unit area while strain is change in length per unit length.

so, if Y is Young's modulus , F is force , A is area and L is length of wire which is changed by ∆L also radius of wire is r.

so, cross section area , A = πr²
now, Young's modulus , Y = FL/(πr²∆L)

now you can see that Young's modulus is inversely proportional to square of radius. if radius of wire is doubled, the Young's modulus will be half.
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