In an experiment of determining young's modulus of the material of a wire,the length as well as radius of the wire is doubled .the young's modulus will
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Young's modulus is the ratio of stress to strain.
where, stress is the force per unit area while strain is change in length per unit length.
so, if Y is Young's modulus , F is force , A is area and L is length of wire which is changed by ∆L also radius of wire is r.
so, cross section area , A = πr²
now, Young's modulus , Y = FL/(πr²∆L)
now you can see that Young's modulus is inversely proportional to square of radius. if radius of wire is doubled, the Young's modulus will be half.
where, stress is the force per unit area while strain is change in length per unit length.
so, if Y is Young's modulus , F is force , A is area and L is length of wire which is changed by ∆L also radius of wire is r.
so, cross section area , A = πr²
now, Young's modulus , Y = FL/(πr²∆L)
now you can see that Young's modulus is inversely proportional to square of radius. if radius of wire is doubled, the Young's modulus will be half.
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