The area of small rectangular plot is 84meter square the difference between length and width is 5meter; find it's perimeter
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Hi friend,
Here is your answer,
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Let the width be x and length be x+5
Area of plot = 84cm²
x(x+5) = 84
x² + 5x = 84
x² + 5x - 84 = 0
x²+12x-7x-84 = 0
x(x+12)-7(x+12) = 0
(x-7)(x+12) = 0
x = 7 x = -12
Width can not be negative so we will neglect -12 and accept 7.
Therefore width is 7m and length is 12m.
Perimeter of the rectangle = 2*(l+b)
= 2*(7+12)
= 2*19
= 38m
_____________________________________________________________
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Here is your answer,
_____________________________________________________________
Let the width be x and length be x+5
Area of plot = 84cm²
x(x+5) = 84
x² + 5x = 84
x² + 5x - 84 = 0
x²+12x-7x-84 = 0
x(x+12)-7(x+12) = 0
(x-7)(x+12) = 0
x = 7 x = -12
Width can not be negative so we will neglect -12 and accept 7.
Therefore width is 7m and length is 12m.
Perimeter of the rectangle = 2*(l+b)
= 2*(7+12)
= 2*19
= 38m
_____________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
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