Question

In an experiment of electrolytic reduction of alumina, 3 mole of oxygen gas produced at anode.
What amount of aluminium metal (in grams) is produced at cathode electrode with respect to the given amount of oxygen?

answer only in numbers please

Answer 1

Number of equivalents of oxygen = = 36

201.6

5.6

(Equivalent volume of oxygen = 5.6 litre at

NTP)

... Number of equivalents of Al = 36

Mass of aluminium = 36 × 9 g

Number of moles of aluminium = 36 × 9 /27 =

12.