In an experiment, one red dice and one black dice(both are fair) are rolled. What is the probability that, the number on black dice will divide the number on red dice. Number on black dice is multiple of the number on red dice.
Answers
Answer:
there r 2dices they will be thrown 1times n we want group of no. that should be multiple so probability is 1/2
Answer:
14 / 36 and 14 /36 respectively
Step-by-step explanation:
We have two dice one is black and the other one is red:
There will be a total of 36 outcomes.
We have to find the probability of the outcome that the number on black dice divides the number on red dice.
1 divides 1, 2, 3, 4, 5, 6.
2 divides 2, 4, 6.
3 divides 3, 6.
4 divides 4.
5 divides 5.
6 divides 6.
There are 14 number which will be counted as favorable outcomes.
Therefor, probability = favorable outcome / total outcome.
i.e. = 14 / 36.
We have to find the probability that the number on black dice is multiple of number on red dice.
1 is multiple of 1
2 is multiple of 1 and 2.
3 is multiple of 1 and 3.
4 is multiple of 1, 2 and 4
5 is multiple of 1 and 5.
6 is multiple of 1, 2, 3 and 6.
There are 14 number which will be counted in favourable outcome;
probability = favorable outcome / total outcome.
i.e. = 14 / 36.