Physics, asked by sanchit4117, 11 months ago

In an experiment to find the density of a solid, the mass and volume of the solid were found to be 400.3 ± 0.02 g and 75.6 ± 0.01 cm³ respectively. Find the percentage error in the determination of its density.

Answers

Answered by gadakhsanket
7

Dear Student,

◆ Answer -

∆d/d % = 0.0182 %

◆ Explaination -

Given that -

M ± ∆M = 400.3 ± 0.02 g

V ± ∆V = 75.6 ± 0.01 cm³

Density of a solid is given by -

d = M / V

Percentage error in measurement of density will be -

∆d/d % = (∆M/M + ∆V/V) × 100

∆d/d % = (0.02/400.3 + 0.01/75.6) × 100

∆d/d % = 0.0182 %

Therefore, percentage error in determination of density is 0.0182 %.

Best luck dear...

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