Physics, asked by shivendrago6595, 11 months ago

Using the method of dimension, show that 1 joule = 10⁷ erg.

Answers

Answered by HappiestWriter012
0

Let us consider, 1 unit of SI unit of work gives n units of CGS units of work.

We know that, Dimensional formula for Work is

[ML^{2}T^{-2}] \:

Since irrespective of the unit, Work has same dimensions, We can write

1[M _ {1}L _ {1}^{2}T _ {1} ^{-2}] \:  \:  = n[M _ {2}L _ {2}^{2}T _ {2} ^{-2}]  \\  \\ n =  \frac{[M _ {1}L _ {1}^{2}T _ {1} ^{-2}]}{[M _ {2}L _ {2}^{2}T _ {2} ^{-2}]} \\  \\

Here, 1 corresponds to SI, and 2 corresponds to CGS.

In SI, Units are kg, m, s while CGS has g, cm, s

n =  \frac{1kg}{g}  \times ( \frac{m}{cm} ) ^{2}  \times ( \frac{s}{s} ) ^{ - 2}  \\  \\ n =  \frac{ {10}^{3}g }{g}  \times ( \frac{ {10}^{2} cm}{cm} ) ^{2}  \times (1) \\  \\ n =  {10}^{3}  \times ( {10 ^{2} })^{2}  \\  \\ n =  {10}^{3}  \times  {10}^{4}  \\  \\ n = 10 ^{7}

From our earlier discussion,

1 SI unit of work gives n = 10^7 CGS units of work.

Hence, 1 Joule = 10^7 erg.

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