Question

In an experiment to study the relationship between the potential difference across a resistor and the current through it, across a resistor and the current through it, a student recorded the following observation
potential difference (v)
2,3,4.5,5,6.
Current (A) 0.08,0.12,0.15,0.20,0.24.

Answer 1

for 1st potential difference and current

v=IR

1 = 0.1 × R

1/0.1 = R

R = 10

for 2nd set of observation

v=IR

2.2 = 0.2 × R

2.2/0.2 =R

R = 11

for 3rd set of observation

v= IR

3 = 0.6 × R

3/0.6 = R

R = 5

Answer 2

Given:

For the 1st resistor

Potential difference (v1) = 2 V

Current (I1) = 0.08 A

Resistance (R1) = ?

Then, R1 = v1/I1 = 2/0.08 =25Ω

For 2nd resistor

Potential difference (v2) =3 V

Current (I2) = 0.12 A

Resistance (R2) = ?

Then, R2 = v2/I2 =3/0.12 = 25 Ω

For 3rd resistor

Potential difference (v3) = 4.5 V

Current (I3) = 0.15 A

Resistance (R3) = ?

Then, R3 = v3/I3 =4.5/0.15 =30 Ω

For 4th resistor

Potential difference (v4) = 5 V

Current (I4) = 0.20 A

Then, R4 = v4/I4 =5/0.20 = 25 Ω

For 5th resistor

Potential difference (v5) = 6 V

Current (I5) = 0.24 A

Resistance (R5) = ?

Then, R5 = v5/I5 = 6/0.24 = 25 Ω

Thus, increase in potential difference across the resistors increases the

current flowing through them i.e (V∝I).