Question

in an given ap sum of the three consecutive terms is 27 and product is 504 ​

Answer 1

Answer:

Let the three term be a- d, a, a+ a

Sum of these three term is

a-d+a+a+d=3a

so, 3a=27

a= 9

Also, we are given product of number

(a-d)×a+×(a+d)= 5o4

(a2-d2) ×a=504

putting a=9

(a2-d2)×9=504

81-d2= 504/9=56

de=81-56=25

so, d=5or -5

9-5,9,9+5

4,9,14