In an hydrogen atom if the energy of electron in the ground state is- ve ev.then that in the 2 nd excited state of he is
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Answered by
136
Firstly it should be He+ ion, not helium
2nd exited state is 3rd bohr orbit
E= -13.6× Z²/n²
-Ve=-13.6×1/1
Ve=13.6eV
energy of electron in 3rd orbit of He+ion is
=-13.6× 4/9= -4Ve/9 eV
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2nd exited state is 3rd bohr orbit
E= -13.6× Z²/n²
-Ve=-13.6×1/1
Ve=13.6eV
energy of electron in 3rd orbit of He+ion is
=-13.6× 4/9= -4Ve/9 eV
please mark me brainliest
Answered by
10
Answer:
answer will be - 6.8 electron volt because it's question in the second orbit of h e plus two that means and equal to three so n equal to 2 sorry n equal to 2 so n equal to 3.4 and when we double it then 3 into 3 3 into 2 6 8 in 4 into 2 that means it cancel the reminder 6.8 electron volt
Explanation:
hope it will help you
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